二进制转十进制--(栈)

2018-01-25 10:57:52来源:网络收集作者:咖啡不加糖人点击

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[var1]/*****************
*每个二进制数转换成相应的十进制数方法如下:
*(XnXn-1……X3X2X1)2 = X1*2^0+X2*2^1+…+Xn*2^(n-1)
*一个二进制数要转换为相应的十进制数,就是从最低位起用每一位去乘以对应位的积,也就是说用第n位去乘以2^(n-1),然后全部加起来。
***************/
#include
#include
#include
#define OK 1
#define ERROR 0
#define STACK_INIT_SIZE 10
#define STACKINCREMENT 5
typedef int ElemType;
typedef int STATUS;
typedef struct Stack {
ElemType * top;
ElemType *base;
int stackSize;
}stack;
STATUS initStack(stack * s)
{
s->base = (ElemType*)malloc(STACK_INIT_SIZE * sizeof(ElemType));
s->top = s->base;
s->stackSize = STACK_INIT_SIZE;
return OK;
}
STATUS Push(stack *s, ElemType e)
{
if (s->top - s->base >= s->stackSize)
{
s->base = (ElemType*)realloc(s->base, (s->stackSize + STACKINCREMENT) * sizeof(ElemType));
if (!s->base)return ERROR;
s->top = s->base + s->stackSize;
s->stackSize = s->stackSize + STACKINCREMENT;
}
*(s->top) = e;
s->top++;
return OK;
}
STATUS Pop(stack *s, ElemType * e)
{
if (s->base == s->top)return ERROR;
--s->top;
*e = *(s->top);
return OK;
}
STATUS clearStack(stack *s)
{
s->top = s->base;
return OK;
}
STATUS destoryStack(stack *s)
{
//for (int i = 0; i < s->stackSize; i++)
//{
free(s->base);
//s->base++;
//}
//printf("%d", *(s->base));
s->base = 0;
s->top = 0;
s->stackSize = 0;
return OK;
}
int main(int argc, char * argv[])
{
stack s;
int data,sum=0,j=0;
ElemType e = 555, q;
initStack(&s);
printf("请输入二进制数每输入一位回车。(-1结束):/n");
scanf("%d", &data);
Push(&s, data);
while (1)
{
scanf("%d", &data);
if (data == -1)break;
Push(&s, data);
};
//开始计算
while (Pop(&s, &data) == OK)
{
sum += data*pow(2, j);
++j;
}
printf("/n十进制数为:%d/n", sum);
//清理
clearStack(&s);
destoryStack(&s);
system("pause");
return 0;
}
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