LeetCode 537. Complex Number Multiplication

2018-02-06 09:42:22来源:https://www.liuchuo.net/archives/4455作者:柳婼 の blog人点击

Given two strings representing two complex numbers.

You need to return a string representing their multiplication. Note i2 = -1 according to the definition.

Example 1:

Input: “1+1i”, “1+1i”

Output: “0+2i”

Explanation: (1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i, and you need convert it to the form of 0+2i.

Example 2:

Input: “1+-1i”, “1+-1i”

Output: “0+-2i”

Explanation: (1 – i) * (1 – i) = 1 + i2 – 2 * i = -2i, and you need convert it to the form of 0+-2i.

Note:

The input strings will not have extra blank.

The input strings will be given in the form of a+bi, where the integer a and b will both belong to the range of [-100, 100]. And the output should be also in this form.

class Solution {
public:
string complexNumberMultiply(string a, string b) {
char t[200];
int m, n, p, q;
sscanf(a.c_str(), "%d+%di", &m, &n);
sscanf(b.c_str(), "%d+%di", &p, &q);
sprintf(t, "%d+%di", (m*p-n*q), (n*p+m*q));
string ans = t;
return ans;
}
};