ajax+php实现无刷新验证手机号

2017-12-14 20:00:07来源:CSDN作者:hjw453321854人点击

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一款简单的无刷新验证手机号是否注册:


客户端实现:

<!DOCTYPE html><html><head><meta charset="utf-8"><style>#btn{width:80px;height:30px;}</style></head><body><form> 请输入手机号:<input type="text" id="name" name="name"><input type="button" onclick="show()" id="btn" value="验证"></form><p id="txt"></p><script>var usernamereg = /^1(3|4|5|7|8)/d{9}$/;function show(){	var name=document.getElementById("name").value;var xmlHttp=new XMLHttpRequest();var url="post.php";xmlHttp.onreadystatechange=function stateChanged() { if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete"){  	if(!usernamereg.test(name)){ 		document.getElementById("txt").innerHTML="手机号有误";	}else{ 	document.getElementById("txt").innerHTML=xmlHttp.responseText  		}  	}}xmlHttp.open("POST",url,true);xmlHttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");xmlHttp.send("name=" + name);} </script></body></html>


服务端实现:

<?php$con = mysqli_connect('localhost', 'username', 'password');if(! $con ){    die('连接失败: ' . mysqli_error($con));}mysqli_select_db($con,'bdm256727651_db');$username = "select userName FROM Forms where userName = '$_POST[name]' ";$result = mysqli_query($con,$username );$rows=mysqli_num_rows($result);if($rows){	echo "手机号已注册"	;	exit;}else{	echo "手机号可用";	}mysqli_close($con)?>



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